How To Convert 10-Byte Long Doubles to 8-Byte Doubles

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This article was previously published under Q129209

SUMMARY

With the 16-bit Microsoft C/C++ compilers, long doubles are stored as 80- bit (10-byte) data types. Under Windows NT, in order to be compatible with other non-Intel floating point implementations, the 80-bit long double format is aliased to the 64-bit (8-byte) double format.

This means that 32-bit programs may not be able read back data files written by 16-bit programs because the long double formats are incompatible.

On Intel platforms, the only workaround is to let the floating point processor handle the conversion from 80-bit to 64-bit doubles. Afterwards, the data can be stored back into a 64-bit double for use under Win32.

The sample code below illustrates how you could use floating point instructions in inline assembly to convert from a 10-byte double in a data file to an 8-byte double.

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Sample Code

/* Compile options needed: none
*/ 

#include <stdio.h>

void main(void)
{
   FILE *inFile;
   char buffer[10];
   long double Newdbl;

   inFile = fopen("data","rb");
   fread(buffer, 10, 1, inFile);      // reads in 10-byte long double
   fclose(inFile);

   // This moves the contents of the buffer into the floating point
   // register, which then then takes care of the automatic convertion
   // back to a 8-byte long double

   _asm {
      fld TBYTE PTR buffer;
      fstp Newdbl;
   }
}

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APPLIES TO

Microsoft Visual C++ 1.0 Professional Edition
Microsoft Visual C++ 2.0 Professional Edition
Microsoft Visual C++ 2.1
Microsoft Visual C++ 4.0 Standard Edition
Microsoft Visual C++ 5.0 Standard Edition
Microsoft Visual C++ 6.0 Service Pack 5

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kbcompiler kbhowto KB129209

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Retired KB Content Disclaimer

This article was written about products for which Microsoft no longer offers support. Therefore, this article is offered "as is" and will no longer be updated.

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