BUG: Using Intrinsic Versions of log10 and fmod

In some cases, using the intrinsic versions of log10 and fmod together in a program may produce incorrect results. The sample code below illustrates the problem.

When the result of log10 is a negative whole number that is divided by 1.0 using fmod, the result of fmod will be -1.0 rather than 0.0. This only occurs when the compiler generates the intrinsic versions of these functions. You need to use the /Oi compiler option to have the compiler generate intrinsic versions of functions.

When using log10 and fmod together in a function, as in the sample code, do not use the /Oi compiler option.

Microsoft has confirmed this to be a bug in the Microsoft products listed at the beginning of this article. We are researching this problem and will post new information here in the Microsoft Knowledge Base as it becomes available.

   /* Compile options needed: /Oi
   */ 
   #include <math.h>
   #include <stdio.h>

   void main()
   {
       double dValue, theLog, theMod;

       dValue = 0.01;
       theLog = log10( dValue );
       theMod = fmod( theLog, 1.0 );

       printf( "The log10 of %f is %f\n", dValue, theLog );
       printf( "The fmod of (%f,1.0) is %f\n", theLog, theMod );
       printf( "for  all x, fmod(x, 1.0) should always be 0.0\n" );
   }