FIX: UPDATE of Table Column with a FOREIGN KEY Constraint May Fail with Msg 8623

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Article ID: 214818 - View products that this article applies to.
This article was previously published under Q214818
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BUG #: 53943 (SQLBUG_70)
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Attempting to update a column using a declared variable may fail if that column has a FOREIGN KEY (FK) constraint and the FROM clause references multiple tables. In such cases, the following error message occurs:
Server: Msg 8623, Level 16, State 2, Line 8
Internal Query Processor Error: The query processor could not produce a query plan.
For example, the following would cause the error:
declare @c1 int
select @c1 =
   update secondary_tbl set c1 = @c1
   from secondary_tbl p,child_1 t1, child_2 t2
   where  p.s1 = t1.s1


To work around this problem, use CONVERT to cast the variable to its data type. In the preceding example, replace:
update secondary_tbl set c1 = @c1

update secondary_tbl set c1 = convert(int,@c1)


Microsoft has confirmed this to be a problem in SQL Server 7.0. This problem has been corrected in U.S. Service Pack 2 for Microsoft SQL Server 7.0. For more information, click the following article number to view the article in the Microsoft Knowledge Base:
254561 INF: How to Obtain Service Pack 2 for Microsoft SQL Server 7.0 and Microsoft Data Engine (MSDE) 1.0
For more information, contact your primary support provider.


Article ID: 214818 - Last Review: October 14, 2013 - Revision: 2.1
  • Microsoft SQL Server 7.0 Standard Edition
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