Oprava: Objekty nelze serializovat spr�vn� p�i serializaci a deserializaci objektech DataSet pomoc� parametru form�t SerializationFormat.Binary aplikace zalo�en� na rozhran� .NET Framework 2.0

Kroky pro reprodukci probl�mu

1. Vytvo�en� nov� aplikace konzoly s n�zvem "ConsoleAppTestDTset".
2. Vytvo�it novou polo�ku DataSet s n�zvem "DsTest.xsd".
3. P�idat tabulku typu objektu DataTable s n�zvem "dtTest".
4. P�idat dva sloupce, kter� jsou pojmenov�ny col1 a col2 do tabulky. Ujist�te se, �e datov� typy jednotliv�ch sloupc� nastaven k System.Int32.
5. Nastavte n�sleduj�c� v�raz "sloupec 2":
   col1 * 2
6. V metod� hlavn� vlo�te n�sleduj�c� k�d:

   static void Main(string[] args)
           {
               // Create a dataset instance.
               DataSet ds = new DsTest();
               // Add a row.
               ds.Tables["dtTest"].Rows.Add(1);
               ds.Tables["dtTest"].Rows.Add(2);
               ds.Tables["dtTest"].Rows.Add(3);
               // Show rows to see that the expression works
               foreach (DataRow dr in ds.Tables["dtTest"].Rows)
               {
                   Console.WriteLine("col1: {0}, col2: {1}", dr[0], dr[1]);
               }
               Console.WriteLine("Expression = " + ds.Tables["dtTest"].Columns["col2"].Expression);
               Console.WriteLine();
               // Do the serialization or the deserialization.
               byte[] serializedDS;
               ds.SchemaSerializationMode = SchemaSerializationMode.ExcludeSchema;
               // Using SerializationFormat.Binary fails.
               ds.RemotingFormat = SerializationFormat.Binary;
               // Using SerializationFormat.Xml works.
               //ds.RemotingFormat = SerializationFormat.Xml;
               
               // Serialize.
               MemoryStream ms = new MemoryStream();
               BinaryFormatter bf = new BinaryFormatter();
               bf.Serialize(ms, ds);
               serializedDS = ms.ToArray();
   
               // Deserialize.
               ms.Write(serializedDS, 0, serializedDS.Length);
                                        ms.Position = 0;
               DataSet newDs = (DataSet)bf.Deserialize(ms);
               // Display the deserialized dataset.
               foreach (DataRow dr in newDs.Tables["dtTest"].Rows)
               {
                   Console.WriteLine("col1: {0}, col2: {1}", dr[0], dr[1]);
               }
               Console.WriteLine("Expression = " + newDs.Tables["dtTest"].Columns["col2"].Expression);
               Console.WriteLine();
   
               Console.WriteLine("Done..!");
               Console.Read();
           }

   When you run the application, the expression string is not displayed in the Output Window as expected.
7. V souboru DsTest.Designer.cs, vyhledejte n�sleduj�c� k�d:

   [System.Diagnostics.DebuggerNonUserCodeAttribute()]protected DsTest(System.Runtime.Serialization.SerializationInfo info, System.Runtime.Serialization.StreamingContext context) : base(info, context, false) 
   {
      if ((this.IsBinarySerialized(info, context) == true)) 
      {
         this.InitVars(false);   
         System.ComponentModel.CollectionChangeEventHandler schemaChangedHandler1 = new System.ComponentModel.CollectionChangeEventHandler(this.SchemaChanged);   
         this.Tables.CollectionChanged += schemaChangedHandler1;   
         this.Relations.CollectionChanged += schemaChangedHandler1;   
         return;
      }
   ...
   

8. Nahradit tento k�d pomoc� n�sleduj�c� k�d:

   [System.Diagnostics.DebuggerNonUserCodeAttribute()]protected DsTest(System.Runtime.Serialization.SerializationInfo info, System.Runtime.Serialization.StreamingContext context) : base(info, context, false) 
   {
      if ((this.IsBinarySerialized(info, context) == true)) 
      {
         this.InitVars(false);   
         System.ComponentModel.CollectionChangeEventHandler schemaChangedHandler1 = new System.ComponentModel.CollectionChangeEventHandler(this.SchemaChanged);   
         this.Tables.CollectionChanged += schemaChangedHandler1;   
         this.Relations.CollectionChanged += schemaChangedHandler1;
    
         // These two lines are the only new ones.
         if ((this.DetermineSchemaSerializationMode(info, context) == System.Data.SchemaSerializationMode.ExcludeSchema))      
            this.InitExpressions();
    
         return;
      }
   ...
   

   ulo�it a znovu spus�te aplikaci, v�raz �et�zec zobrazen� v okn� v�stupu.

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