This article was previously published under Q135379
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Advanced: Requires expert coding, interoperability, and multiuser skills.
When you add a record to an SQL table by using Visual Basic forApplications, if the table's unique index field has a default value, andyou do not assign a value to that field, the new record appears deleteduntil you reopen the SQL table. If you try to obtain a value from the newrecord, you receive the following error message:
Run-time error '3167' Record is deleted.
When you open the SQL table by using Visual Basic code, include thedbSeeChanges option, as in the following example:
Set rs = db.OpenRecordset("TestTable", dbOpenDynaset, dbSeeChanges)
The dbSeeChanges option ensures that any newly added records that containa default value in the unique index field are available in the currentrecordset.
This behavior is by design.
Steps to Reproduce Behavior
Create a module and type the following line in the Declarations section if it is not already there:
Type the following procedure:
Function TestSQLData() Dim db As Database, rs As Recordset Dim idx, td Dim cmd As String ' Delete TestTable if it exists on the SQL server. Set db = OpenDatabase("", False, False,ODBC;dsn=<datasource>; _ database=<database>;uid=<user id>;pwd=<password>") cmd = "if exists (select * from sysobjects where _ id = object_id('dbo.TestTable'))" cmd = cmd & " drop table TestTable" db.Execute cmd, dbSQLPassThrough ' Create TestTable with one field on SQL server. Set td = db.CreateTableDef("TestTable") td.Fields.Append td.CreateField("Int", dbInteger) td.Fields.Append td.CreateField("String", dbText, 50) db.TableDefs.Append td Set idx = td.CreateIndex("MyIdx") idx.Unique = True idx.Fields.Append idx.CreateField("Int") td.Indexes.Append idx cmd = "create Default TestDef3 as 100" db.Execute cmd, dbSQLPassThrough cmd = "sp_bindefault TestDef3, 'TestTable.Int'" db.Execute cmd, dbSQLPassThrough ' Open table, add a record, and then obtain values. Set rs = db.OpenRecordset("TestTable") rs.AddNew rs!String = "Trial" rs.Update Debug.Print "RecordCount = " & rs.RecordCount rs.MoveFirst Debug.Print "String is " & rs("String") Debug.Print "Int is " & rs("Int") rs.Close End Function
To test this function, type the following line in the Debug window, and then press ENTER:
Note that run-time error '3167' occurs.
For more information about the OpenRecordset method, search the Help Indexfor "OpenRecordset," and then "OpenRecordset method," or ask the MicrosoftAccess 97 Office Assistant.