You are currently offline, waiting for your internet to reconnect

# How to use code to derive a statistical median

This article has been archived. It is offered "as is" and will no longer be updated.
Advanced: Requires expert coding, interoperability, and multiuser skills.

##### SUMMARY
This article shows you how to create a Visual Basic for Applicationsprocedure to open a table, read the data, and find the statistical median. The median is a measure of central tendency, another "middle" measurement of a data set, like the mean or average). The data set consisting of the numbers 1, 2, 3, 6, and 100 has a median of 3, the middle of the set. The data set consisting of the numbers 1, 2, 6, and 10 has a median of 4, the middle of the set [(2 + 6) / 2 = 4].
Microsoft provides programming examples for illustration only, without warranty either expressed or implied. This includes, but is not limited to, the implied warranties of merchantability or fitness for a particular purpose. This article assumes that you are familiar with the programming language that is being demonstrated and with the tools that are used to create and to debug procedures. Microsoft support engineers can help explain the functionality of a particular procedure. However, they will not modify these examples to provide added functionality or construct procedures to meet your specific requirements. Note The sample code in this article uses Microsoft Data Access Objects. For this code to run correctly, you must reference the Microsoft DAO 3.6 Object Library. To do so, click References on the Tools menu in the Visual Basic Editor, and make sure that the Microsoft DAO 3.6 Object Library check box is selected.To create a procedure that determines the statistical median of a setof numbers, follow these steps:
1. Create a module and type the following line in the Declarations section:
Option Explicit
2. Type or paste the following procedure.
``Function Median (tName As String, fldName As String) As Single  Dim MedianDB As DAO.Database  Dim ssMedian As DAO.Recordset  Dim RCount As Integer, i As Integer, x As Double, y As Double, _      OffSet As Integer  Set MedianDB = CurrentDB()  Set ssMedian = MedianDB.Openrecordset("SELECT [" & fldName & _            "] FROM [" & tName & "] WHERE [" & fldName & _             "] IS NOT NULL ORDER BY [" & fldName  & "];")  'NOTE: To include nulls when calculating the median value, omit  'WHERE [" & fldName & "] IS NOT NULL from the example.  ssMedian.MoveLast  RCount% = ssMedian.RecordCount  x = RCount Mod 2  If x <> 0 Then     OffSet = ((RCount + 1) / 2) - 2     For i% = 0 To OffSet        ssMedian.MovePrevious     Next i     Median = ssMedian(fldName)  Else     OffSet = (RCount / 2) - 2     For i = 0 To OffSet        ssMedian.MovePrevious     Next i     x = ssMedian(fldName)     ssMedian.MovePrevious     y = ssMedian(fldName)     Median = (x + y) / 2  End If  If Not ssMedian Is Nothing Then     ssMedian.Close     Set ssMedian = Nothing  End If  Set MedianDB = NothingEnd Function``

### How to Use the Median() Function

Create a form and add a text box control where you want to display themedian values of a data set. Set the ControlSource property of the text box control to the following:
``=Median("<TableName>", "<FieldName>")				``
The value of this control is the median of the data set. Another wayto use this function is to call it from within another function thatcompares the median from different data sets. For example:
``   Function CompareMedians()      Dim MyDB as Database      .      .      .      X = Median("<TableName>", "<FieldName>")      Y = Median("<TableName>", "<FieldName>")      If X > Y Then Debug.Print "The median for X is greatest."   End Function				``
statistics
Properties

Article ID: 210581 - Last Review: 12/05/2015 11:34:37 - Revision: 4.0

• Microsoft Access 2000 Standard Edition
• kbnosurvey kbarchive kbhowto kbprogramming KB210581