KB2499023 - Ispravka: Netačni rezultati kada složeni upit za ažuriranje koristi operator JOIN u planu izvršavanja u SQL Server 2008 ili SQL Server 2008 R2

Simptomi

Kada pokrenete složeni upit za ažuriranje koji koristi operator JOIN u planu izvršavanja u sistemu Microsoft SQL Server 2008 ili Microsoft SQL Server 2008 R2, možete dobiti netačne rezultate. Napomena Upit za ažuriranje može da sadrži podkcerije, agregatne funkcije i odredbu DISTINCT. Ako pokrenete isti upit u sistemu Microsoft SQL Server 2008 ili Microsoft SQL Server 2008 R2 Parallel Data Warehouse, možda ćete dobiti još jedan skup netačnih rezultata. Na primer, možete dobiti netačne rezultate kada pokrenete sledeći kôd:

UPDATE RB SET rb1 = (SELECT AVG(DISTINCT T2_1.C1) AS C1 FROM (SELECT DISTINCT T3_1.C3 AS C1, T3_1.C5 AS C2 FROM (SELECT T5_1.c2 AS C1, T5_1.c2 AS C2, T5_1.c3 AS C3, T5_1.c3 AS C4, T5_1.c2 AS C5 FROM DC AS T5_1 UNION SELECT T5_1.c2 AS C1, T5_1.c3 AS C2, T5_1.c2 AS C3, T5_1.c2 AS C4, T5_1.c3 AS C5 FROM DC AS T5_1) AS T3_1) AS T2_1 WHERE (T2_1.C1 = rb3)), rb2 = (SELECT COUNT_BIG(DISTINCT T2_1.C1) AS C1 FROM (SELECT DISTINCT T3_1.C1 AS C1 FROM (SELECT T5_1.rc2 AS C1 FROM RC AS T5_1 UNION ALL SELECT T5_1.c3 AS C1 FROM DC AS T5_1) AS T3_1) AS T2_1 WHERE (T2_1.C1 > rb1)), rb3 = (SELECT COUNT_BIG(*) AS C1 FROM (SELECT DISTINCT T3_1.C1 AS C1, T3_1.C2 AS C2, T3_1.C3 AS C3, T3_1.C4 AS C4, T3_1.C5 AS C5, T3_1.C6 AS C6, T3_1.C7 AS C7, T3_1.C8 AS C8, T3_1.C9 AS C9, T3_1.C10 AS C10 FROM (SELECT T5_1.b2 AS C1, T5_1.b1 AS C2, T5_1.b3 AS C3, T5_1.b2 AS C4, T5_1.b2 AS C5, T5_1.b2 AS C6, T5_1.b2 AS C7, T5_1.b1 AS C8, T5_1.b2 AS C9, T5_1.b3 AS C10 FROM DB AS T5_1 UNION SELECT T5_1.ra3 AS C1, T5_1.ra3 AS C2, T5_1.ra3 AS C3, T5_1.ra3 AS C4, T5_1.ra2 AS C5, T5_1.ra3 AS C6, T5_1.ra1 AS C7, T5_1.ra1 AS C8, T5_1.ra1 AS C9, T5_1.ra1 AS C10 FROM RA AS T5_1) AS T3_1) AS T2_1 WHERE (T2_1.C2 <= rb3)) WHERE rb1 IN (SELECT T2_1.C1 AS C1 FROM (SELECT T4_1.a2 AS C1, T4_1.a1 AS C2, T4_1.a1 AS C3, T4_1.a2 AS C4, T4_1.a1 AS C5, T4_1.a2 AS C6, T4_1.a3 AS C7, T4_1.a1 AS C8 FROM DA AS T4_1 WHERE (T4_1.a1 > (SELECT MIN(DISTINCT T5_1.b3) AS C1 FROM DB AS T5_1 WHERE (T5_1.b3 <= T4_1.a1))) UNION ALL SELECT T4_1.a2 AS C1, T4_1.a2 AS C2, T4_1.a1 AS C3, T4_1.a1 AS C4, T4_1.a1 AS C5, T4_1.a1 AS C6, T4_1.a1 AS C7, T4_1.a3 AS C8 FROM DA AS T4_1) AS T2_1);

Uzrok

Do ovog problema dolazi zbog greške u optimizatoru upita sistema SQL Server.

Rešenje

Status

Microsoft je potvrdio da je ovo problem u Microsoft proizvodima koji su navedeni u odeljku "Odnosi se na".

Reference

Za više informacija o paralelnom skladištu podataka posetite sledeću Microsoft Web lokaciju:

Opšte informacije o paralelnom skladištu podatakaZa više informacija o postepenom modelu servisiranja za SQL Server kliknite na sledeći broj članka da biste videli članak u Microsoft bazi znanja:

935897 Sql Server tim je dostupan u SQL Server timu za isporuku hitnih ispravki za prijavljene problemeZa više informacija o šemi imenovanja za ispravke sistema SQL Server kliknite na sledeći broj članka da biste videli članak u Microsoft bazi znanja:

822499 Nova šema imenovanja za pakete softverskih ispravki za Microsoft SQL ServerZa više informacija o terminologiji softverskih ispravki kliknite na sledeći broj članka da biste videli članak u Microsoft bazi znanja:

824684 Opis standardne terminologije koja se koristi za opisivanje Microsoft softverskih ispravki